A | B | C | D | E | |
A | 0 | - | - | - | - |
B | 20 | 0 | - | - | - |
C | 60 | 50 | 0 | - | - |
D | 100 | 90 | 40 | 0 | - |
E | 90 | 80 | 50 | 30 | 0 |
A & B are
closest (20 units): join them
into one cluster (AB) joining at 20, and
recalculate the average distance from C, D, and E
to (AB). [For example, the distance from C to
(AB) = (60 + 50)/2 = 55, and the distance
from D to (AB) = (100 + 90)/2 = 95].
This gives a new 4x4 matrix with an (AB) pair:
(AB) | C | D | E | |
(AB) | 0 | - | - | - |
C | 55 | 0 | - | - |
D | 95 | 40 | 0 | - |
E | 85 | 50 | 30 | 0 |
D & E are
closest (30 units):
join them into one cluster (DE) joining at 30, and
recalculate the average distances between (AB), C,
and (DE). [For example, the distance from (AB) to (DE)
= (95 + 85)/2 = 90]. This gives a new 3x3
matrix with (AB) and (DE) pairs:
(AB) | C | (DE) | |
(AB) | 0 | - | - |
C | 55 | 0 | - |
(DE) | 90 | 45 | 0 |
C & (DE) are
closest (45 units):
join them into one cluster (CDE) joining at 45, and
recalculate the average distance between (CDE) and (AB).
This
gives a 2x2 cluster, with only one value:
(AB) | (CDE) | |
(AB) | 0 | - |
(CDE) | 72.5 | 0 |
The two clusters join at 72.5. This completes the analysis. [Comment on calculations]
These results
may be presented as a phenogram with nodes at 20,
30, 45, and 72.5 units. Note that these are
values are the calculated pairings in the algorithm. The phenogram
indicates that A & B are most similar
to each other, followed by D & E, and that C
is more similar to D & E. The phenogram of
similarity would have the same shape as a cladogram of
relationship, if and only if rates of change were absolutely
constant.