F is also the proportion
of population that is inbred at any locus:
the fraction of individuals with two alleles identical by
descent.
Then, homozygosity
at any locus indicates identity by descent
In the absence of
inbreeding, expected f(AA) = p2
f(AB) = 2pq
f(BB) = q2
In the presence of
inbreeding,
f(AA) = (1 - F)(p2)
+ (F)(p)(1) = p2
- Fp2 + Fp = p2 + Fp(1 - p)
= p2 + Fpq
fraction (1 - F) of population not inbred:
expected frequency of AA
homozygotes among these = p2
fraction (F) of population inbred:
fraction p of these individuals have
A allele
If inbred, other allele must also be A,
with probability = 1
f(AB) = (1 - F)(2pq)
+ (F)(0) = 2pq -
2Fpq = 2pq (1 - F)
fraction (1- F) of
population not inbred:
the expected frequency of AB
heterozygotes among these is 2pq
fraction (F) of population inbred:
among these, no heterozygotes,
since alleles not identical.
f(BB) = (1 - F)(q2)
+ (F)(q)(1) = q2
- Fq2 + Fq = q2 + Fpq
Follow same logic for f(AA) above, applied to B
allele