Consider a sex-linked locus in a species where females are XX (homogametic) and males are XY (heterogametic). Suppose f(a) is initially unequal in females and males. (1) Because each female receives an X chromosome from both parents in generation n, the female f(a) in generation n+1 is the mean of the male and female f(a) in generation n. (2) Because each male in receives an X chromosome only from the female parent in generation n, the frequency of the allele f(a) in females of generation n automatically determines f(a) in males in generation n+1. The male f(a) therefore "chases" the female f(a) in the preceding generation until they reach approximate equality.
In this example,
note that frequencies are within 1% of each other in the seventh
generation, even when the initial frequencies are completely
divergent.
Note that,
because females contribute two X chromosomes
each and males one X each, the mean f(a)
for a sex-linked locus is a constant (2 x f(a) + 1 x f(a)) / 3 . In this case, (2 x 1 + 1 x 0)
= 0.6667 and remains constant.
HOMEWORK:
Suppose initial f(a) = 0.0
in females, and f(a) = 1.0
in males. Calculate & graph the expected allele
and genotype frequencies in males & females over the
first seven generations.