[Note than alleles can be identical by allelic state without being identical by descent]
F is also the proportion of the population that is inbred (has two alleles identical by descent).
What is the effect of inbreeding on genotype proportions?
In the absence of inbreeding,
expected
f(AA) = p2
f(AB) = 2pq
f(BB) = q2
In the presence of inbreeding,
f(AA) = (1-F)(p2)
+
(F)(p)(1) = p2 - Fp2 + Fp
= p2 + Fp(1-p) = p2
+ Fpq
[A
fraction (1-F) of the population is not inbred:
the
expected frequency of AA homozygotes among these is p2
A fraction (F) of the population is inbred:
a
fraction p of these individuals have one A allele.
Since
they are inbred, the other allele must also be allele A
with a probability = 1]
f(AB) = (1-F)(2pq) +
(F)(0)
= 2pq - 2Fpq = 2pq
(1 - F)
[A fraction (1-F) of the
population
is not inbred:
the
expected frequency of AB heterozygotes among these is 2pq.
A fraction (F) of the population is inbred:
among
these, none can be heterozygotes, since both alleles are
identical.]
f(BB) = (1-F)(q2) +
(F)(q)(1)
= q2 - Fq2 + Fq = q2
+ Fpq
[Same logic as for f(AA) above, applied to B allele]